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2.用JAVA编写的常规科学计算器源代码
3.用C语言写的计算器源代码
4.java 写的计算器源代码只实现加减乘除四则运算即可
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#include
#include
#include
#include
#include
#include
#include
#include
#include
/* Define constants for the calculator */
#define UP 0x
#define DOWN 0x
#define LEFT 0x4B
#define RIGHT 0x4D
#define ENTER 0x0D
/* Global variables */
double num1 = 0, num2 = 0, result = 0;
char str1[] = ".+-*/知消扒Qc=^%";
char cnum[5], str2[] = "", c;
int x, y, x0, y0, i, j, v, m, n, act, flag = 1;
/* Function prototypes */
void drawboder(void);
void initialize(void);
void computer(void);
void changetextstyle(int font, int direction, int charsize);
void mwindow(char *header);
int specialkey(void);
int arrow();
/* Main function */
int main() {
initialize();
computer();
closegraph();
return 0;
}
/* Initialize the graphics system */
void initialize(void) {
int xasp, yasp;
GraphDriver = DETECT;
initgraph( &GraphDriver, &GraphMode, "" );
ErrorCode = graphresult();
if (ErrorCode != grOk) {
printf("Graphics System Error: %s\n", grapherrormsg(ErrorCode));
exit(1);
}
getpalette( &palette );
MaxColors = getmaxcolor() + 1;
MaxX = getmaxx();
MaxY = getmaxy();
getaspectratio( &xasp, &yasp );
AspectRatio = (double)xasp / (double)yasp;
}
/* Main calculator function */
void computer(void) {
struct viewporttype vp;
int color, height, width;
mwindow("Calculator");
color = 7;
getviewsettings( &vp );
width = (vp.right + 1) / ;
height = (vp.bottom - ) / ;
x = width / 2;
y = height / 2;
setfillstyle(SOLID_FILL, color + 3);
bar( x + width * 2, y, x + 7 * width, y + height );
setcolor( color + 3 );
rectangle( x + width * 2, y, x + 7 * width, y + height );
setcolor(RED);
outtextxy(x + 3 * width, y + height / 2, "0.");
x = 2 * width - width / 2;
y = 2 * height + height / 2;
for (j = 0; j < 4; ++j) {
for (i = 0; i < 5; ++i) {
setfillstyle(SOLID_FILL, color);
setcolor(RED);
bar( x, y, x + width, y + height );
rectangle( x, y, x + width, y + height );
sprintf(str2, "%c", str1[j * 5 + i]);
outtextxy( x + (width / 2), y + height / 2, str2);
x += width + (width / 2);
}
y += (height / 2) * 3;
x = 2 * width - width / 2;
}
x0 = 2 * width;
y0 = 3 * height;
x = x0;
y = y0;
gotoxy(x, y);
arrow();
m = 0;
n = 0;
strcpy(str2, "");
while ((v = specialkey()) != ) {
while ((v = specialkey()) != ENTER) {
putimage(x, y, rar, XOR_PUT);
if (v == RIGHT) {
if (x >= x0 + 6 * width)
x = x0;
else
x += width + width / 2;
m++;
}
if (v == LEFT) {
if (x <= x0)
x = x0 + 6 * width;
else
x -= width - width / 2;
m--;
}
if (v == UP) {
if (y <= y0)
y = y0 + 4 * height + height / 2;
else
y -= height - height / 2;
n--;
}
if (v == DOWN) {
if (y >= 7 * height)
y = y0;
else
y += height + height / 2;
n++;
}
putimage(x, y, rar, XOR_PUT);
}
c = str1[n * 5 + m];
if (isdigit(c) || c == '.') {
if (flag == -1) {
strcpy(str2, "-");
flag = 1;
}
sprintf(temp, "%c", c);
strcat(str2, temp);
setfillstyle(SOLID_FILL, color + 3);
bar(2 * width + width / 2, height / 2, * width / 2, 3 * height / 2);
outtextxy(5 * width, height, str2);
}
if (c == '+') {
num1 = atof(str2);
strcpy(str2, "");
act = 1;
setfillstyle(SOLID_FILL, color + 3);
bar(2 * width + width / 2, height / 2, * width / 2, 3 * height / 2);
outtextxy(5 * width, height, "0.");
}
if (c == '-') {
if (strcmp(str2, "") == 0)
flag = -1;
else {
num1 = atof(str2);
strcpy(str2, "");
act = 2;
setfillstyle(SOLID_FILL, color + 3);
bar(2 * width + width / 2, height / 2, * width / 2, 3 * height / 2);
outtextxy(5 * width, height, "0.");
}
}
if (c == '*') {
num1 = atof(str2);
strcpy(str2, "");
act = 3;
setfillstyle(SOLID_FILL, color + 3);
bar(2 * width + width / 2, height / 2, * width / 2, 3 * height / 2);
outtextxy(5 * width, height, "0.");
}
if (c == '/') {
num1 = atof(str2);
strcpy(str2, "");
act = 4;
setfillstyle(SOLID_FILL, color + 3);
bar(2 * width + width / 2, height / 2, * width / 2, 3 * height / 2);
outtextxy(5 * width, height, "0.");
}
if (c == '^') {
num1 = atof(str2);
strcpy(str2, "");
act = 5;
setfillstyle(SOLID_FILL, color + 3);
bar(2 * width + width / 2, height / 2, * width / 2, 3 * height / 2);
outtextxy(5 * width, height, "0.");
用JAVA编写的科学计算器源代码
以下是一个简单的用Java编写的科学计算器的源代码示例:
java
import java.util.Scanner;
public class ScientificCalculator {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Welcome to the Scientific Calculator!");
System.out.println("Enter 'add', 'subtract', 'multiply', 'divide', 'sin', 'cos', 'tan', 'log', 'exp', 'sqrt', or 'quit' to exit.");
while (true) {
System.out.print("Enter operation (e.g., add 2 3): ");
String operation = scanner.nextLine();
if (operation.equalsIgnoreCase("quit")) {
break;
}
String[] parts = operation.split(" ");
double num1 = Double.parseDouble(parts[1]);
double num2 = Double.parseDouble(parts[2]);
switch (parts[0].toLowerCase()) {
case "add":
System.out.println(num1 + " + " + num2 + " = " + (num1 + num2));
break;
case "subtract":
System.out.println(num1 + " - " + num2 + " = " + (num1 - num2));
break;
case "multiply":
System.out.println(num1 + " * " + num2 + " = " + (num1 * num2));
break;
case "divide":
if (num2 != 0) {
System.out.println(num1 + " / " + num2 + " = " + (num1 / num2));
} else {
System.out.println("Error: Division by zero is not allowed.");
}
break;
case "sin":
System.out.println("sin(" + num1 + ") = " + Math.sin(Math.toRadians(num1)));
break;
case "cos":
System.out.println("cos(" + num1 + ") = " + Math.cos(Math.toRadians(num1)));
break;
case "tan":
System.out.println("tan(" + num1 + ") = " + Math.tan(Math.toRadians(num1)));
break;
case "log":
System.out.println("log(" + num1 + ") = " + Math.log(num1));
break;
case "exp":
System.out.println("exp(" + num1 + ") = " + Math.exp(num1));
break;
case "sqrt":
if (num1 >= 0) {
System.out.println("sqrt(" + num1 + ") = " + Math.sqrt(num1));
} else {
System.out.println("Error: Cannot calculate the square root of a negative number.");
}
break;
default:
System.out.println("Error: Invalid operation.");
break;
}
}
scanner.close();
System.out.println("Goodbye!");
}
}
这个科学计算器支持基本的四则运算(加、减、计算乘、器源除)以及一些科学运算(正弦、码常中国最大的源码余弦、规计正切、算器对数、源码指数和平方根)。多少用户可以通过输入相应的常规操作和两个数字来执行计算。例如,计算输入“add 2 3”将计算2加3的器源源码营无忧ppt结果。
代码首先导入了`Scanner`类,码常用于从用户处获取输入。规计然后,算器在`main`方法中,源码创建了一个`Scanner`对象,梦战源码6用于读取用户的输入。程序通过一个无限循环来持续接收用户的输入,直到用户输入“quit”为止。
在循环中,程序首先提示用户输入一个操作,网站源码偷取软件然后读取用户的输入并将其分割为多个部分。接着,程序将第二个和第三个部分转换为`double`类型的数字,并根据第一个部分(即操作)执行相应的计算。
程序使用`switch`语句来根据用户输入的上古卷轴5源码操作执行相应的计算。对于基本的四则运算,程序直接执行相应的计算并输出结果。对于科学运算,程序使用了Java的`Math`类中的相应方法。例如,对于正弦运算,程序使用了`Math.sin`方法,并将角度转换为弧度作为参数传递给它。
如果用户输入了无效的操作或无效
用C语言写的计算器源代码
#include<stdio.h>
#include<iostream.h>
#include<stdlib.h>
#include<string.h>
#include<ctype.h>
typedef float DataType;
typedef struct
{
DataType *data;
int max;
int top;
}Stack;
void SetStack(Stack *S,int n)
{
S->data=(DataType*)malloc(n*sizeof(DataType));
if(S->data==NULL)
{
printf("overflow");
exit(1);
}
S->max=n;
S->top=-1;
}
void FreeStack(Stack *S)
{
free(S->data);
}
int StackEmpty(Stack *S)
{
if(S->top==-1)
return(1);
return(0);
}
DataType Peek(Stack *S)
{
if(S->top==S->max-1)
{
printf("Stack is empty!\n");
exit(1);
}
return(S->data[S->top]);
}
void Push(Stack *S,DataType item)
{
if(S->top==S->max-1)
{
printf("Stack is full!\n");
exit(1);
}
S->top++;
S->data[S->top]=item;
}
DataType Pop(Stack *S)
{
if(S->top==-1)
{
printf("Pop an empty stack!\n");
exit(1);
}
S->top--;
return(S->data[S->top+1]);
}
typedef struct
{
char op;
int inputprecedence;
int stackprecedence;
}DataType1;
typedef struct
{
DataType1 *data;
int max;
int top;
}Stack1;
void SetStack1(Stack1 *S,int n)
{
S->data=(DataType1*)malloc(n*sizeof(DataType1));
if(S->data==NULL)
{
printf("overflow");
exit(1);
}
S->max=n;
S->top=-1;
}
void FreeStack1(Stack1 *S)
{
free(S->data);
}
int StackEmpty1(Stack1 *S)
{
if(S->top==-1)
return(1);
return(0);
}
DataType1 Peek1(Stack1 *S)
{
if(S->top==S->max-1)
{
printf("Stack1 is empty!\n");
exit(1);
}
return(S->data[S->top]);
}
void Push1(Stack1 *S,DataType1 item)
{
if(S->top==S->max-1)
{
printf("Stack is full!\n");
exit(1);
}
S->top++;
S->data[S->top]=item;
}
DataType1 Pop1(Stack1 *S)
{
if(S->top==-1)
{
printf("Pop an empty stack!\n");
exit(1);
}
S->top--;
return(S->data[S->top+1]);
}
DataType1 MathOptr(char ch)
{
DataType1 optr;
optr.op=ch;
switch(optr.op)
{
case'+':
case'-':
optr.inputprecedence=1;
optr.stackprecedence=1;
break;
case'*':
case'/':
optr.inputprecedence=2;
optr.stackprecedence=2;
break;
case'(':
optr.inputprecedence=3;
optr.stackprecedence=-1;
break;
case')':
optr.inputprecedence=0;
optr.stackprecedence=0;
break;
}
return(optr);
}
void Evaluate(Stack *OpndStack,DataType1 optr)
{
DataType opnd1,opnd2;
opnd1=Pop(OpndStack);
opnd2=Pop(OpndStack);
switch(optr.op)
{
case'+':
Push(OpndStack,opnd2+opnd1);
break;
case'-':
Push(OpndStack,opnd2-opnd1);
break;
case'*':
Push(OpndStack,opnd2*opnd1);
break;
case'/':
Push(OpndStack,opnd2/opnd1);
break;
}
}
int isoptr(char ch)
{
if(ch=='+'||ch=='-'||ch=='*'||ch=='/'||ch=='(')
return(1);
return(0);
}
void Infix(char *str)
{
int i,k,n=strlen(str);
char ch,numstr[];
DataType opnd;
DataType1 optr;
Stack OpndStack;
Stack1 OptrStack;
SetStack(&OpndStack,n);
SetStack1(&OptrStack,n);
k=0;
ch=str[k];
while(ch!='=')
if(isdigit(ch)||ch=='.')
{
for(i=0;isdigit(ch)||ch=='.';i++)
{
numstr[i]=ch;
k++;
ch=str[k];
}
numstr[i]='\0';
opnd= atof(numstr);
Push(&OpndStack,opnd);
}
else
if(isoptr(ch))
{
optr=MathOptr(ch);
while(Peek1(&OptrStack).stackprecedence>=optr.inputprecedence)
Evaluate(&OpndStack,Pop1(&OptrStack));
Push1(&OptrStack,optr);
k++;
ch=str[k];
}
else if(ch==')')
{
optr=MathOptr(ch);
while(Peek1(&OptrStack).stackprecedence>=optr.inputprecedence)
Evaluate(&OpndStack,Pop1(&OptrStack));
Pop1(&OptrStack);
k++;
ch=str[k];
}
while(!StackEmpty1(&OptrStack))
Evaluate(&OpndStack,Pop1(&OptrStack));
opnd=Pop(&OpndStack);
cout<<"你输入表达式的计算结果为"<<endl;
printf("%-6.2f\n",opnd);
FreeStack(&OpndStack);
FreeStack1(&OptrStack);
}
void main()
{
cout<<"请输入你要计算的表达式,并以“=”号结束。"<<endl;
char str[];
gets(str);
Infix(str);
=================================================================
哈哈!给分吧!
java 写的计算器源代码只实现加减乘除四则运算即可
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.util.Vector;
public class calculator
{
String str1="0"; //运算数1 初值一定为0 为了程序的安全
String str2="0"; //运算数2
String fh="+"; //运算符
String jg="";//结果
//状态开关 重要
int k1=1;//开关1 用于选择输入方向 将要写入str2或 str2
int k2=1;//开关2 符号键 次数 k2>1说明进行的是2+3-9+8 这样的多符号运算
int k3=1;//开关3 str1 是否可以被清0 ==1时可以 !=1时不能被清0
int k4=1;//开关4 str2 同上
int k5=1;//开关5 控制小数点可否被录入 ==1时可以 !=1 输入的小数点被丢掉
JButton jicunqi; //寄存器 记录 是否连续按下符号键
Vector vt=new Vector(,);
JFrame frame=new JFrame("sunshine---计算器");
JTextField jg_TextField=new JTextField(jg,);//列
JButton clear_Button=new JButton("清除");
JButton button0=new JButton("0");
JButton button1=new JButton("1");
JButton button2=new JButton("2");
JButton button3=new JButton("3");
JButton button4=new JButton("4");
JButton button5=new JButton("5");
JButton button6=new JButton("6");
JButton button7=new JButton("7");
JButton button8=new JButton("8");
JButton button9=new JButton("9");
JButton button_Dian=new JButton(".");
JButton button_jia=new JButton("+");
JButton button_jian=new JButton("-");
JButton button_cheng=new JButton("*");
JButton button_chu=new JButton("/");
JButton button_dy=new JButton("=");
public static void main(String[] args)
{
calculator calculator=new calculator();
}
calculator()
{
jg_TextField.setHorizontalAlignment(JTextField.RIGHT );//文本框 右对齐
JPanel pan=new JPanel();
pan.setLayout(new GridLayout(4,4,5,5));//四行四列 边距为5像素
pan.add(button7);
pan.add(button8);
pan.add(button9);
pan.add(button_chu);
pan.add(button4);
pan.add(button5);
pan.add(button6);
pan.add(button_cheng);
pan.add(button1);
pan.add(button2);
pan.add(button3);
pan.add(button_jian);
pan.add(button0);
pan.add(button_Dian);
pan.add(button_dy);
pan.add(button_jia);
pan.setBorder(BorderFactory.createEmptyBorder(5,5,5,5));//pan对象的边距
JPanel pan2=new JPanel();
pan2.add(jg_TextField);
JPanel pan3=new JPanel(); //为什么要 多此一句呢? 因为我不会设置 按钮的大小
pan3.setLayout(new FlowLayout());
pan3.add(clear_Button);
//clear_Button.setSize(,);//设置清零按钮的大小 吗的 不好使 !!
frame.setLocation(, ); //主窗口 出现在位置
frame.setResizable(false); //不能调大小
frame.getContentPane().setLayout(new BorderLayout());
frame.getContentPane().add(pan2,BorderLayout.NORTH);
frame.getContentPane().add(pan,BorderLayout.CENTER);
frame.getContentPane().add(pan3,BorderLayout.SOUTH);
frame.pack();
frame.setVisible(true);
//以上是 控件 和 布局
//下面是事件处理 程 序
//--------------- 数 字 键 ----------------
class JianTing implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
String ss=((JButton)e.getSource()).getText();
jicunqi=(JButton)e.getSource();
vt.add(jicunqi);
if (k1==1)
{
if(k3==1)
{
str1="";
k5=1;//还原开关k5状态
}
str1=str1+ss;
//k2=1;
k3=k3+1;
//System.out.println(str1);
jg_TextField.setText(str1);//显示
}
else if(k1==2)
{
if (k4==1)
{
str2="";
k5=1; //还原开关k5状态
}
str2=str2+ss;
//k2=2;
k4=k4+1;
///////////////测试////////////////
jg_TextField.setText(str2);
}
}
}
//--------符 号-----------
class JianTing_fh implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
String ss2=((JButton)e.getSource()).getText();
jicunqi=(JButton)e.getSource();
vt.add(jicunqi);
if(k2==1)
{
k1=2;//开关 k1 为1时,向数1写 为2时,向数2写
k5=1;
fh=ss2;
k2=k2+1;//按符号键的次数
}
else
{
int a=vt.size();
JButton c=(JButton)vt.get(a-2); if(!(c.getText().equals("+"))&&!(c.getText().equals("-"))&&!(c.getText().equals("*"))&&!(c.getText().equals("/")))
{
yuns();
str1=jg;
k1=2;//开关 k1 为1时,向数1写 为2时,向数2写
k5=1;
k4=1;
fh=ss2;
} k2=k2+1;
}
}
}
//--------清除-------
class JianTing_clear implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
jicunqi=(JButton)e.getSource();
vt.add(jicunqi);
k5=1;
k2=1;
k1=1;
k3=1;
k4=1;
str1="0";
str2="0";
fh="";
jg="";
jg_TextField.setText(jg);
vt.clear();
}
}
//----------------等 于 ---------------------
class JianTing_dy implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
jicunqi=(JButton)e.getSource();
vt.add(jicunqi);
yuns();
k1=1; //还原开关k1状态
//str1=jg;
k2=1;
k3=1;//还原开关k3状态
k4=1; //还原开关k4状态
str1=jg; //为7+5= +5= 这种计算做准备
}
}
//----------------小数点 ---------------------
class JianTing_xiaos implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
jicunqi=(JButton)e.getSource();
vt.add(jicunqi);
if(k5==1)
{
String ss2=((JButton)e.getSource()).getText();
if (k1==1)
{
if(k3==1)
{
str1="";
k5=1; //还原开关k5状态
}
str1=str1+ss2;
//k2=1;
k3=k3+1;
//System.out.println(str1);
jg_TextField.setText(str1);//显示
}
else if(k1==2)
{
if (k4==1)
{
str2="";
k5=1; //还原开关k5状态
}
str2=str2+ss2;
//k2=2;
k4=k4+1;
///////////////测试////////////////
jg_TextField.setText(str2);
}
}
k5=k5+1;
}
}
//注册 监听器
JianTing_dy jt_dy=new JianTing_dy();
JianTing jt= new JianTing();//临听数字键
JianTing_fh jt_fh= new JianTing_fh();//临 听符 号键
JianTing_clear jt_c=new JianTing_clear(); //清除键
JianTing_xiaos jt_xs=new JianTing_xiaos();// 小数点 键
button7.addActionListener(jt);
button8.addActionListener(jt);
button9.addActionListener(jt);
button_chu.addActionListener(jt_fh);
button4.addActionListener(jt);
button5.addActionListener(jt);
button6.addActionListener(jt);
button_cheng.addActionListener(jt_fh);
button1.addActionListener(jt);
button2.addActionListener(jt);
button3.addActionListener(jt);
button_jian.addActionListener(jt_fh);
button0.addActionListener(jt);
button_Dian.addActionListener(jt_xs);
button_dy.addActionListener(jt_dy);
button_jia.addActionListener(jt_fh);
clear_Button.addActionListener(jt_c);
//关闭事件处理程序
frame.addWindowListener(new WindowAdapter()
{
public void windowClosing(WindowEvent e)
{
System.exit(0);
}
});
}
//---------------计 算------------------
public void yuns()
{
double a2,b2;//运算数1,2
String c=fh;// 运算符
double jg2=0 ;//结果
if (c.equals(""))
{
//System.out.println("请输入运算符");
jg_TextField.setText("请输入运算符");
}
else
{
System.out.println("str1:"+str1);//调试时 使 用
System.out.println("str2:"+str2);//调试时 使 用
System.out.println("运算符:"+fh);//调试时 使 用
if (str1.equals(".")) //字符串 "." 转换成double型数据时 会出错 所以手工转
str1="0.0";
if (str2.equals("."))
str2="0.0";
a2=Double.valueOf(str1).doubleValue();
b2=Double.valueOf(str2).doubleValue();
System.out.println("double型的a2:"+a2); //调试时 使 用
System.out.println("double型的b2:"+b2); //调试时 使 用
if (c.equals("+"))
{
jg2=a2+b2;
}
if (c.equals("-"))
{
jg2=a2-b2;
}
if (c.equals("*"))
{
jg2=a2*b2;
}
if (c.equals("/"))
{
if(b2==0)
{
jg2=0;// by 0 cu!
}
else
{
jg2=a2/b2;
}
}
System.out.println("double型a2"+fh+"b2结果:"+jg2);
System.out.println();
jg=((new Double(jg2)).toString());
jg_TextField.setText(jg);
}
}
}